# Project Euler Problem #1 - Multiples of 3 and 5 (in Python)

```# If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9.
# The sum of these multiples is 23.

# Find the sum of all the multiples of 3 or 5 below 1000.

sum = 0
threeMultiple = False
fiveMultiple = False

for i in range (3, 1000):

threeMultiple = i % 3 == 0
fiveMultiple = i % 5 == 0

if (threeMultiple or fiveMultiple):
sum += i

print (sum)
```

Or you could do this in a one-liner:

``` print (sum ( [i for i in range(3, 1000) if i%3 == 0 or i%5 == 0] ) ) ``` DOWNLOAD

## Explanation of the one-liner:

The `print` function simply prints the return of the `sum([])` function.
The `sum([])` function takes in an array, sums up the values of each element in the list and returns that (the sum - a single numeric value).
The list to pass to `sum([])` is generated in the following code:

``` [i for i in range(3, 1000) if i%3 == 0 or i%5 == 0] ```

This says that the list will include every `i` in the for loop from 3 to 999 of `i` if `i` is a multiple of 3 and/or a multiple of 5. It loops through 3 to 999, checks if `i` is a multiple of 3 and/or 5, and adds it to the list if it is.

After the list is created, the sum of that list is returned and printed.

Created: February 10, 2014
Completed in full by: Michael Yaworski